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The values of x and y vary directly, and when x=48, y=36. Find the value of x when y=18.

Sagot :

When two variables vary directly they follow the next:

[tex]y=k\cdot x[/tex]

k is a constant.

Use the given data: when x=48, y=36 o find the value of k:

[tex]\begin{gathered} 36=k\cdot48 \\ \\ \frac{36}{48}=k \\ \\ k=\frac{3}{4} \end{gathered}[/tex]

Then, x and y vary directly following the next equation:

[tex]y=\frac{3}{4}x[/tex]

Use the equation above to find x when y=18:

[tex]\begin{gathered} 18=\frac{3}{4}x \\ \\ 18(\frac{4}{3})=x \\ \\ x=\frac{18\cdot4}{3} \\ \\ x=\frac{72}{3} \\ \\ x=24 \end{gathered}[/tex]Then, the value of x when y=18 is x=24
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