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The standard form of a square root function is f(x) = sqrt x - h + k. For the function f(x) = sqrt x+ 2 + 1. set (x - h) = 0 and solve for x. Also, what is the value of k? What was the starting point, again?

Sagot :

we are given the following standard form of a function:

[tex]f(x)=\sqrt[]{x-h}+k[/tex]

We are also given the following function:

[tex]f(x)=\sqrt[]{x+2}+1[/tex]

since "x - h" is the term under the radical, we have:

[tex]x-h=x+2[/tex]

setting this value to zero, we get:

[tex]x+2=0[/tex]

To solve for "x" we will subtract 2 to both sides:

[tex]\begin{gathered} x+2-2=-2 \\ x=-2 \end{gathered}[/tex]

"k" is the value we add to the radical, therefore:

[tex]k=1[/tex]

The starting point is:

[tex](h,k)=(-2,1)[/tex]

That is, up one, right two.