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Sagot :
The slope-intercept form of a linear equation is given by:
[tex]y=mx+b[/tex]Where m is the slope and b is the y-intercept.
To calculate the slope, we can use the formula below with the given two points:
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1}\\ \\ m=\frac{-1-14}{2-(-3)}\\ \\ m=\frac{-15}{5}\\ \\ m=-3 \end{gathered}[/tex]Now, to find the value of b, let's use the point (2, -1) in the equation:
[tex]\begin{gathered} y=mx+b\\ \\ -1=-3\cdot2+b\\ \\ -1=-6+b\\ \\ b=-1+6\\ \\ b=5 \end{gathered}[/tex]Therefore the equation is y = -3x + 5.
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