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To which number set(s) does the following number belong ? sqrt(18) Multiple answers may be correct. Mark all correct answers . irrational numbers rational numbers whole numbers counting or natural numbers real numbers integers No number set describes this number.

Sagot :

Answer:

irrational numbers and real numbers

Explanation:

Given:

[tex]\sqrt{18}[/tex]

To find:

the number set the number belongs to

Rational numbers are numbers that can be written in fractional form. The roots of the perfect squares are rational numbers as they give whole numbers.

Irrational numbers are numbers that cannot be written in fractional form. The roots of non-perfect squares are irrational

[tex]\begin{gathered} we\text{ will check if }\sqrt{18}\text{ is a perfect square} \\ \sqrt{18}\text{ = }\sqrt{2\times9}\text{ } \\ =\text{ 3}\sqrt{2} \\ \\ \sqrt{18\text{ }}\text{ is not a perfect square} \end{gathered}[/tex]

Hence, it is an irrational number

Whole numbers are whole with no decimals. Irrational numbers give decimals that do not end

Natural numbers are not irrational as the numbers are whole

Real numbers include both irrational numbers and rational numbers. As a result, √18 is a real number

Integers are natural numbers, opposites, and zero. They do not include decimals. Hence, they are rational

The correct answers are irrational numbers and real numbers