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When heated, KClO3 decomposes into KCl and O2.2KClO3⟶2KCl+3O2If this reaction produced 32.2 g KCl, how many grams of O2 were produced?

Sagot :

Answer: 20.7g of O2 would be produced from the decomposition of KClO3 if 32.2g of KCl were obtained

Explanation:

The question requires us to determine the amount, in grams, of O2 that would be produced in the decomposition reaction of KClO3 when 32.2g of KCl are produced.

The following balanced chemical equation was provided:

[tex]2KClO_3\rightarrow2KCl+3O_2[/tex]

According to the balanced chemical equation above, 3 moles of O2 are obtained when 2 moles of KCl are produced. Thus, we can use this stoichiometric relation to determine the amount of O2 produced.

The problem presented is a mass to mass stoichiometry problem, therefore we'll need to follow the steps:

mass of KCl → moles of KCl → moles of O2 → mass of O2

These steps mean that we'll first calculate the number of moles of KCl that correspond to the mass of KCl given (32.2g), then use the stoichiometry of the reaction and mole ratio between O2 and KCl to determine the number of moles of O2 produced, and at last use the molar mass of O2 to convert this number of moles to the mass of O2 (the molar mass of KCl is 74.55g/mol, and the molar mass of O2 is 32.00g/mol).

Therefore, we can write the following expression to calculate the mass of O2:

[tex]mass\text{ of O}_2=mass\text{ of KCl}\times\frac{1}{molar\text{ mass KCl}}\times\frac{3mol\text{ }O_2}{2mol\text{ KCl}}\times\frac{molar\text{ mass O}_2}{1}[/tex]

And, applying the appropriate values, we'll have:

[tex]\begin{gathered} mass\text{ of O}_2=32.2g\text{ KCl}\times\frac{1mol\text{ KCl}}{74.55g/mol\text{ KCl}}\times\frac{3mol\text{ O}_2}{2mol\text{ KCl}}\times\frac{32.00g/mol\text{ O}_2}{1} \\ \\ mass\text{ of O}_2=20.7g\text{ O}_2 \end{gathered}[/tex]

Therefore, 20.7g of O2 would be produced from the decomposition of KClO3 if 32.2g of KCl were obtained.