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Sagot :
Given the system of the equation below;
[tex]\begin{gathered} 8x+y=-16----(1) \\ -3x+y=-5----(2) \end{gathered}[/tex]We can use the elimination method to solve the systems of equations
Step 1: Subtract equation 2 from equation 1 and solve for x
[tex]\begin{gathered} 8x+y-(-3x+y)=-16-(-5) \\ 8x+y+3x-y=-16+5 \\ 11x=-11 \\ \frac{11x}{11}=-\frac{11}{11} \\ x=-1 \end{gathered}[/tex]Step 2: Sustitute x = 1 in equation 1
[tex]\begin{gathered} 8(-1)+y=-16 \\ -8+y=-16 \\ y=-16+8 \\ y=-8 \end{gathered}[/tex]Therefore, the solution to the system of equation is
[tex](-1,-8)[/tex]
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