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The mean of 5 consecutive integers is 10. If the smallest of these is removed, what is the new mean? A.8.4 B.9.0 C.10.5 D.12.5

Sagot :

number 1 = x

number 2 = x + 1

number 3 = x + 2

number 4 = x + 3

number 5 = x + 4

then

[tex]\begin{gathered} \frac{x+x+1+x+2+x+3+x+4}{5}=10 \\ \frac{5x+10}{5}=10 \\ \frac{5x+10}{5}\cdot5=10\cdot5 \\ 5x+10=50 \\ 5x+10-10=50-10 \\ 5x=40 \\ \frac{5x}{5}=\frac{40}{5} \\ x=8 \end{gathered}[/tex]

therefore the numbers are:

number 1 = 8

number 2 = 9

number 3 = 10

number 4 = 11

number 5 = 12

and the new media is:

[tex]M=\frac{9+10+11+12}{4}=\frac{42}{4}=10.5[/tex]

answer: C. 10.5