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Find the length of the third side. If necessary, round to the nearest tenth. 12 13

Sagot :

[tex]\text{H}^2=a^2+b^2[/tex]

Where

H = Hypotenuse (side oposite to the angle of 90 °)

a and b = legs (other sides of triangule)

[tex]\begin{gathered} \text{H}^2=a^2+b^2 \\ 13^2=12^2+b^2 \\ 169=144+b^2 \\ 25=b^2 \\ b=\sqrt[]{25} \\ b=5 \end{gathered}[/tex]

QUESTION 2

H = 13 cm

a = 9 cm

[tex]\begin{gathered} \text{H}^2=a^2+b^2 \\ 13^2=9^2+b^2 \\ 169=81+b^2 \\ 169-81=b^2 \\ 88=b^2 \\ b=\sqrt[]{88} \\ b=9.40 \end{gathered}[/tex]

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