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Sagot :
Given the linear function below,
[tex]-6x+5y=-10[/tex]The general form of the equation of a straight line in the "slope-intercept form" is given below as,
[tex]\begin{gathered} y=mx+c \\ \text{Where m is the slope} \\ c\text{ is the y-intercept} \end{gathered}[/tex]To find the slope and y-intercept of the equation given
Making y the subject below, to find the slope-intercept form
[tex]\begin{gathered} -6x+5y=-10 \\ 5y=6x-10 \\ \text{Divide both sides by 5} \\ \frac{5y}{5}=\frac{6x-10}{5} \\ y=\frac{6}{5}x-2 \end{gathered}[/tex]Since m is the slope and c is the y intercept, to find the slope and intercept of the above equation,
[tex]\begin{gathered} y=mx+c \\ y=\frac{6}{5}x-2 \\ m=\frac{6}{5},c=-2 \end{gathered}[/tex]Hence, the slope, m = 6/5 and the y-intercept, c = -2
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