Answered

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i need help with understand how to solve literal equations,this one in particular

I Need Help With Understand How To Solve Literal Equationsthis One In Particular class=

Sagot :

The given equation is

[tex]-12x+8y=-48[/tex]

The equation has 2 variables (x and y)

To solve it, we have to assume a value of x and get its corresponding value of y

Let x = 1, then substitute it in the equation and solve it to find y

[tex]\begin{gathered} x=1 \\ -12(1)+8y=-48 \\ -12+8y=-48 \end{gathered}[/tex]

Add 12 to both sides

[tex]\begin{gathered} -12+12+8y=-48+12 \\ 0+8y=-36 \\ 8y=-36 \end{gathered}[/tex]

Divide both sides by 8

[tex]\begin{gathered} \frac{8y}{8}=\frac{-36}{8} \\ y=-4.5 \end{gathered}[/tex]

At x = 1, y = -4.5

Then one solution of the equation is (1, -4.5)

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