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rectFind the equation in slope-intercept form) of the line with the given slope that passes through the pointwith the given coordinates.slope:2- 32ordered pair: (-3,-2)AncilorKeypad

RectFind The Equation In Slopeintercept Form Of The Line With The Given Slope That Passes Through The Pointwith The Given Coordinatesslope2 32ordered Pair 32Anc class=

Sagot :

Answer:

[tex]y=-\frac{3}{2}x-\frac{13}{2}[/tex]

Explanations:

The equation of a line in point-slope form is expressed as:

[tex]y-y_0=m(x_{}-x_0)[/tex]

where:

• m is the, slope ,of the line

,

• (x0, y0) is, any point ,on the line

Given the following parameters

[tex]\begin{gathered} m=-\frac{3}{2} \\ (x_0,y_0)=(-3,-2) \end{gathered}[/tex]

Substitute the given parameters into the formula to have:

[tex]\begin{gathered} y-(-2)=-\frac{3}{2}(x_{}-(-3)) \\ y+2=-\frac{3}{2}(x+3) \\ 2(y+2)=-3(x_{}+3) \end{gathered}[/tex]

Expand and write in slope-intercept form y = mx + b

[tex]\begin{gathered} 2y+4=-3x-9 \\ 2y=-3x-9-4 \\ 2y=-3x-13 \\ y=-\frac{3}{2}x-\frac{13}{2} \end{gathered}[/tex]

Hence the equation of the line in slope-intercept form is expressed as

y = -3/2x - 13/2

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