Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
Given:
Function is:
[tex]P(v)=\begin{cases}0.7v+u\text{ if }_0\leq v\leq90 \\ 0.7v\text{ if }v>90\end{cases}[/tex]Find-:
(a)
Value of P(100)
(b)
Average rate of change [ 30, 120]
(c)
Function is linear or not
(d)
P(v)=v
Explanation-:
Value of P(100)
[tex]\begin{gathered} P(100)\text{ is:} \\ \\ v>90 \\ \\ P(v)=0.7v \\ \\ P(100)=0.7\times100 \\ \\ P(100)=70 \end{gathered}[/tex](b)
Average rate of change
[tex]P(v)=\begin{cases}0.7v+u\text{ if}0\leq v\leq90 \\ 0.7v\text{ if}v>90\end{cases}[/tex][tex]P^{\prime}(v)=\begin{cases}0.7 \\ 0.7\end{cases}[/tex]u is constant is then the rate of change is 0.7
(c)
A linear equation is:
Function is:
[tex]y=mx+c[/tex]The given function is a linear function.
(d)
For equilibrium
[tex]\begin{gathered} P(v)=v \\ \\ \end{gathered}[/tex]Check for v
[tex]\begin{gathered} P(v)=v \\ \\ 0.7v+u=v \\ \\ u=0.6v \end{gathered}[/tex]at u = 0.6v function value is equilibrium.
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.