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Sagot :
Explanation:
First we have to eliminate the parenthesis by applying the distributive property for the addition:
[tex]\begin{gathered} \frac{1}{7}(14-7p)-2=-2(\frac{1}{2}p+3)+6_{} \\ \frac{14}{7}-\frac{7p}{7}-2=-\frac{2}{2}p-3\cdot2+6 \\ \text{ simplifying} \\ 2-p-2=-p-6+6 \end{gathered}[/tex]Now we have to add the terms that have numbers on each side:
[tex]\begin{gathered} -p+(2-2)=-p+(6-6) \\ -p=-p \end{gathered}[/tex]We can see that both sides of the equation are the same. This means that this equation doesn't have only one solution, because any number we put in p will make the equation true.
Answer:
Many solutions
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