Answered

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12. Write the equation of a straight line that is parallel to y + 3x = 6 and thatpasses through the point (3,-4).a. y = 3x - 13b. y=-3x+13c. y = 4x +6d. y=-3x - 5e. y=-3x + 5

Sagot :

y+3x = 6

First put the equation in slope intercept form ( y = mx+b) where m is the slope and b is the y intercept

y = -3x+6

The slope is -3

Since we want the lines to be parallel, they will have the same slope m = -3

Equation of new line

y = mx+b

y = -3x+b

We have a point on the line

(3,-4)

Substitute this point in for x and y and determine b

-4 = -3(3) +b

-4 = -9+b

Add 9 to each side to isolate b

-4+9 = -9+9+b

5 = b

y = -3x+5

The equation of a line that is parallel to 3x=6 and goes through (3,-4) is

y = -3x+5

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