Answered

Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

12. Write the equation of a straight line that is parallel to y + 3x = 6 and thatpasses through the point (3,-4).a. y = 3x - 13b. y=-3x+13c. y = 4x +6d. y=-3x - 5e. y=-3x + 5

Sagot :

y+3x = 6

First put the equation in slope intercept form ( y = mx+b) where m is the slope and b is the y intercept

y = -3x+6

The slope is -3

Since we want the lines to be parallel, they will have the same slope m = -3

Equation of new line

y = mx+b

y = -3x+b

We have a point on the line

(3,-4)

Substitute this point in for x and y and determine b

-4 = -3(3) +b

-4 = -9+b

Add 9 to each side to isolate b

-4+9 = -9+9+b

5 = b

y = -3x+5

The equation of a line that is parallel to 3x=6 and goes through (3,-4) is

y = -3x+5

Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.