The pressure value is given as,
[tex]P=240\text{ kPa}[/tex]The value of the area is given as
[tex]\begin{gathered} A=190cm^2 \\ A=190\times10^{-4}m^2 \end{gathered}[/tex]Thus, total area for the four tires is,
[tex]\begin{gathered} A^{\prime}=4\times A \\ A^{\prime}=4\times190\times10^{-4} \\ A^{\prime}=760\times10^{-4}m^2 \end{gathered}[/tex]The force exerted in terms of pressure and area is,
[tex]\begin{gathered} F=P\times A^{\prime} \\ F=240\times10^3\times760\times10^{-4} \\ F=18240\text{ N} \end{gathered}[/tex]According to the newton's law,
[tex]F=mg[/tex]where g is the acceleration due to gravity.
Substituting the known values,
[tex]\begin{gathered} 18240=m\times9.8 \\ m=\frac{18240}{9.8} \\ m=1861.2\text{ kg} \end{gathered}[/tex]Thus, the value of the mass of the car is 1861.2.
