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Sagot :
Answer: 7.8125x10^-22 electrons.
Calculations:
• Let ,x , represent electron in a body.
,• use the following formula tocalculagte excess electrons acquired.
,• Charge = 125mC /10000 =1.25 x10^-2
[tex]\begin{gathered} \text{Charge = electron }\cdot\text{ electron charge } \\ 1.25X10^{-2\text{ }}=\text{ x }\cdot1.6X10^{-19} \\ x\text{ = }\frac{1.25X10^{-2}}{1.6X10^{-19}} \\ \text{ }\therefore x\text{= }7.8125X10^{-22} \end{gathered}[/tex]This means that there are 7.8125x10^-22 excess electron aqcuired.
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