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Sagot :
The mirror image of a line about origin will be obtained by replacing x with -x and y with -y.
Therefore, the mirror image of the line 4y = 3x + 7 will be:
[tex]\begin{gathered} 4(-y)=3(-x)+7 \\ -4y=-3x+7 \end{gathered}[/tex]Rearranging the equation, we have:
[tex]3x-4y=7[/tex]Note that a dilation always preserves parallelism. Therefore, any image formed from the preimage must have the same slope.
Therefore, we can say that the dilation will yield the equation:
[tex]3x-4y=k[/tex]where k is a constant.
Going by this, the equation that can represent its image will be:
[tex]3x-4y=9[/tex]OPTION 1 is correct.
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