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What is the magnitude of the acceleration caused by the force of kinetic friction acting on a box sliding across a level table? The coefficient of friction is 0.22

Sagot :

The kinetic friction formula is

[tex]F=\mu mg[/tex]

Where mu = 0.22 and g = 9.8 m/s^2.

[tex]\begin{gathered} F=0.22\cdot m\cdot9.8N \\ F=2.2mN \end{gathered}[/tex]

Therefore, the kinetic friction is 2.2m Newtons.

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