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I need help with this problem I been stuck on it for hours

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Sagot :

The average rate of change of height is

[tex]\frac{\Delta H}{\Delta t}[/tex]

(a).

From 0 seconds to 2.3 seconds

[tex]\Delta t=2.3s-0s=2.3s[/tex]

and

[tex]\Delta H=92m-0m=92m[/tex]

Therefore,

[tex]\frac{\Delta H}{\Delta t}=\frac{92m}{2.3s}=\textcolor{#FF7968}{\frac{40m}{s}}[/tex]

(b).

From 4.6 seconds to 11.5 seconds we have

[tex]\Delta t=11.5s-4.6s=6.9s[/tex]

and

[tex]\Delta H=0m-138m=-138m[/tex]

Therefore,

[tex]\frac{\Delta H}{\Delta t}=\frac{-138m}{6.9s}=\textcolor{#FF7968}{\frac{-20m}{s}}[/tex]

Hence, (a). 40m/s and (b). -20m/s.

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