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Sagot :
Answer:
The number of salespeople to be assigned to each shift is;
[tex]\begin{gathered} \text{Morning }=2 \\ \text{Midday }=4 \\ \text{Afternoon }=6 \\ \text{Evening }=7 \end{gathered}[/tex]Explanation:
Using Hamilton's method.
let d represent the divisor.
[tex]d=\frac{\text{ total average number of customers for the day}}{\text{number of salespeople to be apportioned}}[/tex]total average number of customers for the day is the sum of all the average given;
[tex]105+300+450+475=1330[/tex]The total number of salespeople to be apportioned is given as 19.
the divisor d is;
[tex]\begin{gathered} d=\frac{1330}{19}=70 \\ d=70 \end{gathered}[/tex]To determine number of salespeople N to assign to each shift, we will divide the average number A of customers in that shift by the divisor d.
for morning;
A=105
[tex]\begin{gathered} N=\frac{A}{d}=\frac{105}{70} \\ N=1.5 \end{gathered}[/tex]for midday;
A=300
[tex]\begin{gathered} N=\frac{300}{70} \\ N=4.29 \end{gathered}[/tex]for afternoon;
A=450
[tex]N=\frac{450}{70}=6.43[/tex]for Evening;
A=475
[tex]\begin{gathered} N=\frac{475}{70} \\ N=6.79 \end{gathered}[/tex]To get an exact whole number let us round each up to the nearest whole number.
The final answer is;
[tex]\begin{gathered} \text{Morning }=2 \\ \text{Midday }=4 \\ \text{Afternoon }=6 \\ \text{Evening }=7 \end{gathered}[/tex]
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