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Sagot :
To answer this question we can use the titration formula, which is:
Ma * Va = Mb * Vb
Where:
Ma = molarity of acids
Va = volume of acids
Mb = molarity of bases
Vb = volume of bases
We have the molarity and volume of the acid, and the volume of the base, now let's add to our equation:
0.850M * 25.0 mL = 36.0 mL * Mb
But there is a small detail here, if you check the reaction you will see that the ratio is 2:1, so for every molecule of H2SO4 in a reaction, I will need 2 molecules of NaOH in the reaction so that it all can go forward, and for every NaOH, you will need 1/2 of H2SO4 to move forward in the reaction. So we will add this "2" in the equation.
(0.850M * 25.0 mL)/2 = 36.0 mL * Mb
21.25/2 = 36Mb
10.625 = 36Mb
Mb = 0.295M
Therefore, according to the titration formula, we will have 0.295 of molarity of NaOH in the reaction.
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