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Solve the equation below and find the variation constant, k. Find x when y = 32, if y varies inversely as x, and y = 10 when x = 40

Sagot :

Given: y=10 then x=40

We use cross multiplication and set it up as a fraction.

[tex]\frac{x}{40}=\frac{32}{10}\text{ }\Rightarrow10x=32*40\text{ }\Rightarrow10x=1280\Rightarrow\frac{10x}{10}=\frac{1280}{10}[/tex]

So you just divide 10 on both sides to get x by itself.

Answer: x=128