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Sagot :

Given the quadratic equation:

[tex]4x^2+8x+4[/tex]

Factorizing the common factor:

[tex]4(x^2+2x+1)[/tex]

But we know that:

[tex](x+1)^2=x^2+2x+1[/tex]

Now, using this identity:

[tex]4x^2+8x+4=4(x+1)^2[/tex]

We conclude that the factoring pattern is a perfect square trinomial

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