Answered

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What is an equation of the line that passes through the point (6, 1) and is parallel tothe line x + 3y= 15?

Sagot :

Paralell to line x + 3y = 15

Passes through (6, 1)

First we have to write the line equation in the form y = mx + b to know the slope:

x + 3y = 15

3y = -x + 15

y = (-x + 15)/3 = (-1/3)x + 5

y = (-1/3)x + 5

Therefor the slope is (-1/3)

The equation of the line would be: y = (-1/3)x + b, and since it passes throug (6,1), we can use these values to fin b:

y = (-1/3)x + b

1 = (-1/3)6 + b

1 = -2 + b

1 + 2 = b

b = 3

So the equation we are looking for is y = (-1/3)x + 3

Answer:

y = (-1/3)x + 3

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