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Sagot :
Given that collection of nickels and quarters equals 61, thus;
[tex]Let\text{ n represents nickels and q represents quarters}[/tex][tex]n+q=61\ldots\ldots\ldots\ldots\ldots\text{equation 1}[/tex]Also, 1 dollar is equal to 20 nickels;
Hence 1 nickel is 1/20 dollars = $0.05;
Similarly, 1 quarter is $0.25, thus;
[tex]0.05n+0.25q=6.85\ldots\ldots\ldots\ldots\ldots\text{equation 2}[/tex]Solving the two equations simultaneously;
[tex]\begin{gathered} \text{From equation 1}, \\ n=61-q\ldots\ldots\ldots\ldots\ldots\ldots\text{.}\mathrm{}\text{equation 3} \\ \text{Put equation 3 in equation 2;} \\ 0.05(61-q)+0.25q=6.85 \\ 3.05-0.05q+0.25q=6.85 \\ 0.2q=6.85-3.05 \\ 0.2q=3.8 \\ q=\frac{3.8}{0.2} \\ q=19 \end{gathered}[/tex][tex]\begin{gathered} \text{Put q=19 in equation 3;} \\ n=61-q \\ n=61-19 \\ n=42 \end{gathered}[/tex]Hence, Azlyn has 42 nickels and 19 quarters
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