From the given right triangle we get that:
[tex]\sin H=\frac{FG}{HF}\text{.}[/tex]
Multiplying the above equation by HF we get:
[tex]\begin{gathered} \sin H\times HF=\frac{FG}{HF}\times HF, \\ HF\sin H=FG\text{.} \end{gathered}[/tex]
Substituting HF=7 and H=25 degrees in the above equation we get:
[tex]\begin{gathered} FG=7\sin 25^{\circ}, \\ FG\approx3.0. \end{gathered}[/tex]
Answer:
[tex]FG\approx3.0.[/tex]
