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Sagot :
Graphing a system of equations
We will choose two points, when x=0 and when x=1, so we can graph two points for each line
First point: when x = 0
2x + y = -4
2 · 0 + y = -4
0 + y = -4
y = -4
(0, -4)
y = -1/2x + 2
y = -1/2 · 0 + 2
y = 0 + 2
y = 2
(0, 2)
Second point: when x=1
2x + y = -4
2 · 1 + y = -4
2 + y = -4
y = -4 - 2
y = -6
(1, -6)
y= -1/2x + 2
y= -1/2 + 2
y = 3/2
(1, 3/2)
We draw a line that passes through the pair of points of the first equation:
(0, -4) and (1, -6)
and the pair of points of the second:
(0, 2) and (1, 3/2)
Finding the solution
We know that the solution is given by the intersect of the two lines,
We can observe that they intersect each other at the point x = -4 and y = 4
The solution is x=-4 and y=4: (-4, 4)




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