To solve this question we will use the following diagram:
From the diagram, we get that the diameter of the semicircle is 8cm.
The perimeter of the figure is:
[tex]P=14\operatorname{cm}+4\operatorname{cm}+6\operatorname{cm}+\pi\cdot8\operatorname{cm}\text{.}[/tex]
Substituting π=3.14 and simplifying we get:
[tex]\begin{gathered} P=14\operatorname{cm}+4\operatorname{cm}+6\operatorname{cm}+25.12\operatorname{cm}, \\ P=49.12\operatorname{cm}\text{.} \end{gathered}[/tex]
Now, the area of the given figure is the area of the rectangle plus the area of the semicircle:
[tex]A=14\operatorname{cm}\times4\operatorname{cm}+\frac{\pi\cdot(4\operatorname{cm})^2}{2}\text{.}[/tex]
Substituting π=3.14 and simplifying we get:
[tex]\begin{gathered} A=56cm^2+25.12cm^2, \\ A=81.12cm^2. \end{gathered}[/tex]
Answer:
[tex]\begin{gathered} \text{Perimeter}=\text{ 49.12cm,} \\ \text{Area}=\text{ 81.12 cm}^2. \end{gathered}[/tex]
