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solve the quation exactly on 0 less greater than t less greater than 2 phi. solve this: sin t: -1

Sagot :

To answer this question, we have that we need to find the values for t where the tangent function will be equal to zero.

We have that:

[tex]\tan t=0[/tex]

And, if we see that the function tangent is equal to:

[tex]\tan t=\frac{\sin t}{\cos t}[/tex]

We need to find, in the interval:

[tex]0\leq t\leq2\pi[/tex]

The values for which sin(t) = 0. If we see the unit circle, the points, in this interval, where sin(t) = 0 are t = 0, t = pi, and t = 2*pi.

Therefore, we have that the points for tan(t) = 0 are, therefore (in the given interval):

[tex]\tan t=0,t=0,t=\pi,t=2\pi[/tex]

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