Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

The figure shows a uniform, horizontal beam of length = 7 m and mass = 50 kg that ishanging by two cables as shown. If a person of mass = 60 kg stands at 3.6 m from the leftend, what are the tensions (T1 and T2) in the cables? Write only the answer to T2 incanvas (in newtons).T1T2

The Figure Shows A Uniform Horizontal Beam Of Length 7 M And Mass 50 Kg That Ishanging By Two Cables As Shown If A Person Of Mass 60 Kg Stands At 36 M From The class=

Sagot :

Given:

• Length of beam = 7 m

,

• Mass of beam = 50 kg

,

• Mass of person = 60 kg

,

• Distance of the person from the left = 3.6 m

Let's find the tensions, T1 and T2.

First make a free body sketch:

Here, the net torque = 0.

To find the tension, T1, we have:

[tex]T_1*l-m_Pg*(l-l_1)-m_bg*\frac{l}{2}=0[/tex]

Where:

l = 7 m

mp = 60 kg

g is acceleration due to gravity = 9.8 m/s²

l1 = 3.6 m

mb = 50 kg

Thus, we have:

[tex]\begin{gathered} T_1*7-60*9.8*(7-3.6)-50*9.8*\frac{7}{2}=0 \\ \\ T_1*7-1999.2-1715=0 \\ \\ T_1=\frac{3714.2}{7} \\ \\ T_1=530.6\text{ N} \\ \end{gathered}[/tex]

Therefore, the tension T1 = 530.6 N.

To find the tension T2, we have:

[tex]\begin{gathered} T_2*7-60*9.8*3.6-50*9.8*3.5=0 \\ \\ T_2*7-2116.8-1715=0 \\ \\ T_2*7=2116.8+1715 \\ \\ T_2=\frac{2116.8+1715}{7} \\ T_2=547.4\text{ N} \\ \end{gathered}[/tex]

Thererfore the tension T2 = 547.5 N

• ANSWER:

T1 = 530.6 N

T2 = 547.4 N

View image EbrahimW13046
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.