Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
Question: Liliana has $3.80 in nickels and quarters in her purse. She has 22 more nickels than quarters. How many coins of each type does she have?
Solution:
Liliana has $3.80 in nickels and quarters in her purse.
She has 22 more nickels than quarters.
We first have to establish a system of equations. Since we have two unknown variables, we need to have two equations. The first equations;
let x = number of quarters
x+22 = number of nickels
The total worth of coins = $3.80
The value of a quarter is $0.25 and the value of a nickel is $0.05.
According to the problem:
[tex]0.25x+0.05(x+22)=3.80[/tex]Applying the distributive property, we get:
[tex]0.25x+0.05x+1.1\text{ = 3.80}[/tex]this is equivalent to:
[tex]0.25x\text{ +0.05x = 3.80}-1.1[/tex]this is equivalent to:
[tex]0.3x=2.7[/tex]Solving for x, we obtain:
[tex]x=\text{ }\frac{2.7}{0.3}=9[/tex]Thus, we obtain that:
The number of quarters = x = 9
number of nickels = x+22 = 9+22 = 31
So t
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.
