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Sagot :
Answer:
9.24 g of KCl.
Explanation:
What is given?
Mass of Fe(NO3)3 = 10.0 g.
Molar mass of Fe(NO3)3 = 242 g/mol.
Mlar mass of KcCl = 74.5 g/mol. (you can calculate the molar massesof a compound using the periodc table)
Step-by-step solution:
Let's covert 110.0 g of Fe(NO3)3 to moles using is molar mass, like this:
[tex]1\text{0.0 g Fe\lparen NO}_3)_3\cdot\frac{1\text{ mol Fe\lparen NO}_3)_3}{242\text{ g Fe\lparen NO}_3)_3}=0.0413\text{ moles Fe\lparen NO}_3)_3.[/tex]You can see in the chemical equation that 3 moles of KCl are required to react with 1 mol of Fe(NO3)3, so by doing a rule o three to find how many moles of KClowe require to react with 0.0413 moles Fe(NO3)3, the calculation will look this:
[tex]0.0413\text{ moles Fe\lparen NO}_3)_3\cdot\frac{3\text{ moles KCl}}{1\text{ mol Fe\lparen NO}_3)_3}=0.124\text{ moles KCl.}[/tex]And the final step is to convert 0.124 moles of KCl to grams using its given molar mass, likethis:
[tex]0.124\text{ moles KCl}\cdot\frac{74.5\text{ g KCl}}{1\text{ mol KCl}}=9.238\text{ g KCl}\approx9.24\text{ g KCl.}[/tex]We will require 9.24 g of KCl to react with 10.0 g of Fe(NO3)3.
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