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Sagot :
A quadratic equation can be written in the vertex form to be:
[tex]y=a(x-h)^2+k[/tex]where (h, k) is the vertex.
The question gives the following parameters:
[tex]\begin{gathered} (h,k)=(1,0) \\ (x,y)=(0,1) \end{gathered}[/tex]We can use these values to solve for a:
[tex]\begin{gathered} 1=a(0-1)^2+0 \\ a=1 \end{gathered}[/tex]Therefore, the vertex form of the quadratic equation will be:
[tex]y=(x-1)^2[/tex]Expanding, we have the general form of the quadratic equation to be:
[tex]f(x)=x^2-2x+1[/tex]
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