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Sagot :
Explanation:
The molarity of a solution is defined like the number of moles of solute per liters of solution.
Molarity = moles of solute/(volume of solution in L)
We have to find the number of moles of NaCl that are present in 0.6 L of a 1.55 M solution. So we know the volume in liters and the molarity of the solution. We can solve the formula for the number of moles of NaCl and get the answer to our problem.
molarity = 1.55 M
volume of solution = 0.6 L
molarity = moles of NaCl/volume of solution
moles of NaCl = molarity * volume of solution
moles of NaCl = 1.55 M * 0.6 L
moles of NaCl = 0.93 moles
Answer: there are 0.93 moles of NaCl present in the solution.
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