SOLUTION
The eccentricity is the measure of how much the ellipse deviates from a circle.
The eccentricity of an ellipse which is not a circle is greater than zero but less than 1.
For an ellipse, the eccentricity is giving as
[tex]\frac{\sqrt[]{a^2-b^2}}{a}[/tex]where
[tex]\begin{gathered} a^2=50,a=\sqrt[]{50}=5\sqrt[]{2} \\ b^2=9,b=\sqrt[]{9}=3 \end{gathered}[/tex]Substitute the value into the formula we have
[tex]\begin{gathered} \frac{\sqrt[]{50-9}}{5\sqrt[]{2}} \\ \text{Then } \\ \frac{\sqrt[]{41}}{5\sqrt[]{2}} \end{gathered}[/tex]Then rationalize the expression in the last line
[tex]\frac{\sqrt[]{41}\times\sqrt[]{2}}{5\sqrt[]{2}\times\sqrt[]{2}}=\frac{\sqrt[]{82}}{10}=0.9055[/tex]Hence the eccentricity of the ellipse is approximately 0.91
Since the value of a is much larger than b, then it indicates that the ellipse is
More Elongated than circular.