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Help with for review to study for finals next week.

Help With For Review To Study For Finals Next Week class=

Sagot :

The exponential function involving doubling period is expressed as

P = Po(2)^t/T

where

Po is the initial or starting value

t is the time of growth

T is the doubing time

t/T is the ratio describing the number of doubings over time t

From the information given,

T = 15

t = 80

P = 80000

We want to find Po

We have

80000 = Po(2)^80/15

80000 = 40.32Po

Po = 80000/40.32 = 1984

The initial population is 1984

Thus, the function is

P = 1984(2)^t/15

For 3 hours, recall,

1 hour = 60 minutes

3 hours = 3 * 60 = 180 minutes

We would substitute t = 180 into the equation. We have

P = 1984(2)^180/15 = 1984(2)^12

P = 8126464

The size of the bacterial population after 3 hours is 8126464