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f(x) = (2x + 4)/(3x + 2) Consider the function For this function there are two important intervals: (- ∞, A) and (A, ∞) where the function is not defined at A. Find A

Fx 2x 43x 2 Consider The Function For This Function There Are Two Important Intervals A And A Where The Function Is Not Defined At A Find A class=

Sagot :

Given:

The function

[tex]f(x)=\frac{2x+4}{3x+2}[/tex]

Required:

Find all parts.

Explanation:

Domain:

The domain of a function is the set of all possible inputs for the function.

Increasing and Decreasing of a function:

The derivative of a function may be used to determine whether the function is increasing or decreasing on any intervals in its domain. If f′(x) > 0 at each point in an interval I, then the function is said to be increasing on I. f′(x) < 0 at each point in an interval I, then the function is said to be decreasing on I.

Concavity:

A function f is concave up (or upwards) where the derivative f' is increasing. This is equivalent to the derivative of f', which is f'', being positive. Similarly, f is concave down (or downwards) where the derivative f' is decreasing (or equivalently, f'', is negative).

The graph of a function:

Now, the function defined on

[tex]=(-\infty,-\frac{2}{3})\cup(-\frac{2}{3},\infty)[/tex]

Where the function is not defined at A

[tex]A\text{ }is\text{ }x=-\frac{2}{3}[/tex][tex]\begin{gathered} \text{ For each of the following interval function is decreasing on}: \\ (-\infty,-\frac{2}{3})\cup(-\frac{2}{3},\infty). \end{gathered}[/tex]

Also,

[tex]\begin{gathered} \text{ Function is concave upward on }(-\frac{2}{3},\infty). \\ \text{ Function is concave downward on }(-\infty,-\frac{2}{3}). \end{gathered}[/tex]

Answer:

Completed the question.

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