Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Given:
[tex]\begin{gathered} x\text{ + 6y = 29 eqn (1)} \\ 2x\text{ - 4y = -6 eqn (2)} \end{gathered}[/tex]Using Substitution method:
From equation (1):
[tex]x\text{ + 6y = 29}[/tex]Make x the subject of formula:
[tex]x\text{ = -6y + 29}[/tex]Substituting back into equation (2):
[tex]\begin{gathered} 2x\text{ - 4y = -6} \\ 2(-6y\text{ + 29) -4y = -6} \\ -12y\text{ + 58 -4y = -6} \end{gathered}[/tex]Collect like terms:
[tex]\begin{gathered} -12y\text{ - 4y = -6 - 58} \\ -\text{ 16y = -64} \end{gathered}[/tex]Divide both sides by -16:
[tex]\begin{gathered} \frac{-16y}{-16}\text{ = }\frac{-64}{-16} \\ y\text{ = 4} \end{gathered}[/tex]Substituting 4 for y into the equation (1):
[tex]\begin{gathered} x\text{ + 6y = 29} \\ x\text{ }+\text{ 6(4) = 29} \\ x\text{ + 24 = 29} \\ x\text{ = 29 - 24} \\ x\text{ = 5} \end{gathered}[/tex]Hence, the solution to the simultaneous equation is:
x =5, y = 4
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.
