Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Hi, can you help me answer this question, please, thank you!

Hi Can You Help Me Answer This Question Please Thank You class=

Sagot :

Given,

The mean of the test score is 1013.

The standard deviation of the test score is 125.

The percentage of cutoff is 9%.

The z score at 9% is,

[tex]Z=1.35[/tex]

The z score is calculated as,

[tex]z=\frac{X-\operatorname{mean}}{s\tan dard\text{ deviation}}[/tex]

Substituting the value of z, mean and standard deviation then,

[tex]\begin{gathered} 1.35=\frac{X-1013}{125} \\ 168.75=X-1013 \\ X=1182 \end{gathered}[/tex]

Hence, the cutoff for the top 9% is 1182.

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.