Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Let the universal Set be s. Let A and B are subsets of S. Set contains 90 elements and Set B contains 99 elements. Set A and B have 21 elements in common. If there are 24 elements that are in S but not in A nor B, how many elements are in S ?

Sagot :

Given

Set A contains = 90 elements

Set B contains = 99 elements

A and B contains = 21 elements

Find

number of elements in Set S

Explanation

As we know

[tex]n(A\cup B)=n(A)+n(B)-n(A\cap B)[/tex]

so,

[tex]n(A\cup B)=90+99-21=168[/tex]

Total elements in S = elements in A or B + elements not in A or B

so,

[tex]168+24=192[/tex]

Final Answer

Total elements in S = 192

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.