A titration required 47.52 mL of 0.1051 M NaOH to reach the end point whentitrating 30.00 mL of an HCl solution. What is the molar concentration (to 4 sigfigs) of the HCI solution based on this datum?

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03-11-2022
Chemistry

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A titration required 47.52 mL of 0.1051 M NaOH to reach the end point whentitrating 30.00 mL of an HCl solution. What is the molar concentration (to 4 sigfigs) of the HCI solution based on this datum?

Sagot :

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OllyL554429 OllyL554429 · Answer 1 · 2022-11-03T21:34:39-04:00

In order to solve this question, we can use the titration formula, in which we take the volume of both acid and base, and the concentration of the base in order to find the concentration of the acid. The formula is:

Ma*Va = Mb*Vb

We have:

Ma = ?

Va = 30.00 mL of HCl

Mb = 0.1051 M of NaOH

Vb = 47.52 mL of NaOH

Now we add these values into the formula:

Ma*30 = 0.1051*47.52

30Ma = 4.9943

Ma = 0.1665 M is the molar concentration for the acid

A titration required 47.52 mL of 0.1051 M NaOH to reach the end point whentitrating 30.00 mL of an HCl solution. What is the molar concentration (to 4 sigfigs) of the HCI solution based on this datum?

Sagot :

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