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A line's equation is given in point-slope form. y=(-(3/8)),(x+8)+4 A point on this line that is apparent from the given equation is [ ]

Sagot :

To know a point in that line we are going to take x=0 so

[tex]\begin{gathered} y\text{ = }(\frac{-3}{8})(0\text{ + 8) -4} \\ y\text{ = (}\frac{-3}{8}\text{) (8) -4} \\ y\text{ = -3 -4 = -7} \end{gathered}[/tex]

the answer is a point on this line is (0, -7), another point is (-56/3, 0) = (-18.6 , 0)

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