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Which values are solutions to (k-3)/4 >-2? Select two options.k=-10Ok=-7Ok=-5Ok=-1Ok=0

Sagot :

Answer:

k = -1

k = 0

Explanation:

Given

[tex]\frac{k-3}{4}>-2[/tex]

This can be solved as follows:

[tex]\begin{gathered} k-3>-2\times4=-8 \\ \\ k>-8+3=-5 \end{gathered}[/tex]

The options where k > - 5 is true are:

k = -1

k = 0