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Sagot :
Given:
On first day, the number of adult tickets sold, p=9.
On first day, the number of student tickets sold, q=3.
The total price of tickets sold on first day, t=$120.
On second day, the number of adult tickets sold, m=1.
On second day, the number of student tickets sold, n=1.
The total price of tickets sold on second day, T=$22.
Let x be the price of one adult ticket and y be the price of one student ticket.
Hence, the expression for the total price of tickets sold on first day is,
[tex]\begin{gathered} t=px+qy \\ 120=9x+3y\text{ ---(1)} \end{gathered}[/tex]The expression for the total price of tickets sold on second day is,
[tex]\begin{gathered} T=mx+ny \\ 22=x+y\text{ ---}(2) \end{gathered}[/tex]Now, multiply equation (2) by 3.
[tex]\begin{gathered} 3\times22=3x+3y \\ 66=3x+3y\text{ ---(3)} \end{gathered}[/tex]Subtract equation (3) from equation (1) and solve for x.
[tex]\begin{gathered} 120-66=9x+3y-3x-3y \\ 54=6x \\ x=\frac{54}{6} \\ x=9 \end{gathered}[/tex]So, x=9.
Now, substitute x=9 in equation (2) and solve for y.
[tex]\begin{gathered} 22=9+y \\ y=22-9 \\ y=13 \end{gathered}[/tex]Therefore, the price of each adult ticket is $9 and the price of each student ticket is $13.
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