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Equation of a line in slope intercept form and standard form Slope of -1/2 and contains point (-2, 5)

Sagot :

We can use the point slope formula to find the slope intercept form of the equation.

[tex]y-y1=m(x-x1)[/tex]

Where m is the slope and x1 and y1 are the coordinates of the given point. Replace for the given values:

[tex]y-5=-\frac{1}{2}(x-(-2))[/tex]

Now, solve for y to find the slope intercept form of the equation:

[tex]\begin{gathered} y-5=-\frac{1}{2}x-1 \\ y=-\frac{1}{2}x-1+5 \\ y=-\frac{1}{2}x+4 \end{gathered}[/tex]

The equation of the line is:

[tex]y=-\frac{1}{2}x+4[/tex]