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Sagot :
Given:-
Company A charge $80.
Company B charge $65 and $.60 for every mile.
Let x be the number of miles driven in severe an equity.
Company A charge,
[tex]A=80[/tex]Company B charge,
[tex]B=65+0.60x[/tex]Now let A=B. we get,
[tex]\begin{gathered} 80=65+0.60x \\ 80-65=0.60x \\ 15=0.60x \end{gathered}[/tex]Converting $0.06,
[tex]\begin{gathered} 0.60=\frac{60}{100} \\ 0.60=\frac{6}{10} \end{gathered}[/tex]now,
[tex]\begin{gathered} 0.60x=15 \\ \frac{6}{10}x=15 \\ 6x=150 \\ x=\frac{150}{6} \end{gathered}[/tex]Simplifying we get,
[tex]\begin{gathered} x=\frac{150}{6} \\ x=\frac{50}{2} \\ x=25 \end{gathered}[/tex]For milage 25 company A charge less than Company B use him for the number of miles driven in severe an equity for him.
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