Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
Given:-
Company A charge $80.
Company B charge $65 and $.60 for every mile.
Let x be the number of miles driven in severe an equity.
Company A charge,
[tex]A=80[/tex]Company B charge,
[tex]B=65+0.60x[/tex]Now let A=B. we get,
[tex]\begin{gathered} 80=65+0.60x \\ 80-65=0.60x \\ 15=0.60x \end{gathered}[/tex]Converting $0.06,
[tex]\begin{gathered} 0.60=\frac{60}{100} \\ 0.60=\frac{6}{10} \end{gathered}[/tex]now,
[tex]\begin{gathered} 0.60x=15 \\ \frac{6}{10}x=15 \\ 6x=150 \\ x=\frac{150}{6} \end{gathered}[/tex]Simplifying we get,
[tex]\begin{gathered} x=\frac{150}{6} \\ x=\frac{50}{2} \\ x=25 \end{gathered}[/tex]For milage 25 company A charge less than Company B use him for the number of miles driven in severe an equity for him.
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.
