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Sagot :
the formula is:
[tex]a_n=2\cdot n^2+6[/tex]and we need to find a1, a2, a3, a4 and a5
n=1
[tex]\begin{gathered} a_1=2\cdot1^2+6 \\ a_1=2+6=8 \end{gathered}[/tex]n=2
[tex]\begin{gathered} a_2=2\cdot2^2+6 \\ a_2=2\cdot4+6 \\ a_2=8+6=14 \end{gathered}[/tex]n=3
[tex]\begin{gathered} a_3=2\cdot3^2+6 \\ a_3=2\cdot9+6 \\ a_3=18+6=24 \end{gathered}[/tex]n=4
[tex]\begin{gathered} a_4=2\cdot4^2+6 \\ a_4=2\cdot16+6 \\ a_4=32+6=38 \end{gathered}[/tex]n=5
[tex]\begin{gathered} a_5=2\cdot5^2+6 \\ a_5=2\cdot25+6 \\ a_5=50+6=56 \end{gathered}[/tex]so the answer is:
a1=8
a2=14
a3=24
a4=38
a5=56
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