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Solar radiation at the surface of the earth is about 700 W/m2. How much solar energy is incident on a roof of dimensions 7.48 m by 15.16 m in 1.09 hours?

Sagot :

Given:

The intensity of Solar radiation is,

[tex]I=700\text{ W/m}^2[/tex]

The area of the roof is,

[tex]A=7.48\text{ m}\times15.16\text{ m}[/tex]

The time is,

[tex]\begin{gathered} t=1.09\text{ hours} \\ =1.09\times3600\text{ s} \end{gathered}[/tex]

To find:

The incident solar energy

Explanation:

The incident energy is,

[tex]\begin{gathered} E=IAt \\ =700\times7.48\times15.16\times1.09\times3600 \\ =311.5\times10^6\text{ J} \end{gathered}[/tex]

Hence, the incident energy is

[tex]311.5\times10^6\text{ J}[/tex]

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