Answered

Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Get quick and reliable solutions to your questions from a community of experienced professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Solar radiation at the surface of the earth is about 700 W/m2. How much solar energy is incident on a roof of dimensions 7.48 m by 15.16 m in 1.09 hours?

Sagot :

Given:

The intensity of Solar radiation is,

[tex]I=700\text{ W/m}^2[/tex]

The area of the roof is,

[tex]A=7.48\text{ m}\times15.16\text{ m}[/tex]

The time is,

[tex]\begin{gathered} t=1.09\text{ hours} \\ =1.09\times3600\text{ s} \end{gathered}[/tex]

To find:

The incident solar energy

Explanation:

The incident energy is,

[tex]\begin{gathered} E=IAt \\ =700\times7.48\times15.16\times1.09\times3600 \\ =311.5\times10^6\text{ J} \end{gathered}[/tex]

Hence, the incident energy is

[tex]311.5\times10^6\text{ J}[/tex]

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.