Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

find the standard equation for the circle. center (1,2) radius 5

Sagot :

Solution

Step 1

[tex]\begin{gathered} The\text{ general equation of a circle is in the form of} \\ (x-h)^2+(y-k)^2=r^2 \\ \\ Where\text{ \lparen h,k\rparen is the center and r is the radius} \end{gathered}[/tex]

Step 2

Given data:

Center = (h.k) = (1,2) and radius r = 5

Step 3

Substitute the values into the equation.

[tex]\begin{gathered} (x-1)^2+(y-2)^2=5^2 \\ \\ (x-1)^2+(y-2)^2=25 \end{gathered}[/tex]

Final answer

[tex](x-1)^2+(y-2)^2=25[/tex]

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.