Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
To answer this question, we need to have into account the formula for the volume of a cylinder. This formula is given by:
[tex]V=\pi\cdot r^2\cdot h[/tex]1. We have that pi is approximately equal to 3.1415926535...
2. The radius is half of the diameter. In this case, the diameter is 6 feet. Therefore, the radius is 3 feet.
3. The height of the storage tank (cylinder) is h = 10 feet.
Hence, we can plug all of these values into the formula, and we can get the value for the total volume of this cylinder:
[tex]V=\pi\cdot(3^{}ft)^2\cdot10ft\Rightarrow V=\pi\cdot9\cdot10\Rightarrow V=90\pi ft^3[/tex]Now, since the tank is half-filled with oil, we have that the oil, in cubic feet, in the cylindrical tank is half of the value of the previous value, that is:
[tex]\frac{1}{2}V=\frac{1}{2}\cdot(90\pi ft^3)=45\pi ft^3[/tex]Hence, the current volume of oil in the cylindrical tank is:
[tex]45\pi ft^3[/tex](Option C).
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.